Reference, Questions and Help > Nuke Q&A
Half-value layers
Rennhack:
Lead (11.35 g/cm )
Photon Energy(keV) 500 HVL (cm) 0.38
Photon Energy(keV) 1000 HVL (cm) 0.86
Photon Energy(keV) 1500 HVL (cm) 1.2
Photon Energy(keV) 2000 HVL (cm) 1.3
Photon Energy(keV) 3000 HVL (cm) 1.5
cincinnatinuke:
Hey my math works if you are willing to forget Log rules in math. Like since 2^n=4.....then n=2
Therefore, 2^n=10.....n=5 since before 2*2=4 then 2*5=10. It has to be.
But hey lets try it the right way and 2^n=10....n=3.32.., then from a HVL of 0.25in you get 0.83in. approximately for a TVL of lead for Cs-137.
TVL for Tungsten becomes 0.53in fir Cs-137.
Luckily for me I dont have to admit to error due to my disclaimer in my post :) :) :)
Reminds me of a story. NASA buillds a rocket (I believe to orbit some distant planet or something like that)and they have one set of enginneers calculate one set of numbers and give said numbers to another group of engineers. But, since none of them had attended Naval Nuclear Power School and missed points on a test for their mistake, their math made them "Unitless" men in their work. So they missed their mark and found out one group used english units the other thought they were in metric. They probably are still out there looking for their "unit"....of measurement of course....and a new job.
opus_two:
Thanks
I am rebuilding attentuators on one of the irradiator that uses two CS137 sources and three attenuators. The HVL atteuator has the lead insert beat up in it so I want to replace it with a tungsten insert. While I was replacing it we decided to replace all three attenuators instead. The hvl, qvl and tvl.
So I am chasing down tungten values.
I located some alloy values for tungsten from Wolfmet.com at a density of 19.3 vs Lead at 11.3
RDTroja:
--- Quote from: cincinnatinuke on Jun 17, 2005, 01:09 ---Reminds me of a story. NASA buillds a rocket (I believe to orbit some distant planet or something like that)and they have one set of enginneers calculate one set of numbers and give said numbers to another group of engineers. But, since none of them had attended Naval Nuclear Power School and missed points on a test for their mistake, their math made them "Unitless" men in their work. So they missed their mark and found out one group used english units the other thought they were in metric. They probably are still out there looking for their "unit"....of measurement of course....and a new job.
--- End quote ---
That was a Mars lander. Calculations in meters, measurements in feet, results in 'excessive landing speed at incorrect angle' otherwise known as crash. Oops... looks like NASA needs a little three-part-communications training (as well as attention to detail, peer checking, STAR, etc). Guess they got the STAR -- as in 'S**t That Ain't Right!
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