NukeWorker Forum
Reference, Questions and Help => Nuke Q&A => Topic started by: stoicperrin on Oct 06, 2008, 01:43
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My instructor has asked a question that I don't know how to figure out. It is not in the assigned textbook which I have read cover to cover. Perhaps it needs a formula or some information not covered in this part of the class. Anyway here goes.
How many gamma rays are emitted from a 50 curie source of Co 60 in one minute?
Is there some formula to figure this out? Is this one of those so easy questions I am overlooking it?
Is this question even in the right place on this forum? LOL
I asked a couple of other students in my class and none of them have a clue, and the first time I will have to ask the instructor will be when I have to hand it in. :-[
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1 Ci = 3.7E10 dis per second
each decay for Co-60 gives 2 gammas.
You have 50 Ci X3.7E10 dis/sec/Ci X2 gammas/dis X 60 sec/min
Its solved by unit analysis and doesn't need an equation from book.
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ahhh there we go.. even though I didn't put in part of the question you gave me the answer.
or the way to figure it out.
How many gamma rays are emitted from a 50 curie source of Co 60 in one minute?
Was supposed to say..
How many 1.33 Mev gamma rays are emitted from a 50 curie source of Co 60 in one minute?
So 50 Ci x 37 billion dis/sec/ci x1 gamma/dis x 60 sec/min
I didn't know that each disintegration gave off the 2 characteristic gammas.
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ahhh there we go.. even though I didn't put in part of the question you gave me the answer.
or the way to figure it out.
How many gamma rays are emitted from a 50 curie source of Co 60 in one minute?
Was supposed to say..
How many 1.33 Mev gamma rays are emitted from a 50 curie source of Co 60 in one minute?
So 50 Ci x 37 billion dis/sec/ci x1 gamma/dis x 60 sec/min
I didn't know that each disintegration gave off the 2 characteristic gammas.
Here is some future reference material that may be helpful
http://www.nndc.bnl.gov/chart/ (http://www.nndc.bnl.gov/chart/) - an interactive chart of the nuclides
http://www.radprocalculator.com/Index.aspx (http://www.radprocalculator.com/Index.aspx) - the Rad Pro Calculator - a handy tool by Ray McGinnis
Then there is the study tab at the top of the website here - lots of information.
So, what course are you taking?
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May be a trick question cause gamma's per second and disintegrations per second aint the same thing.
For Co-60 there are 3.699E4 gamma's per second per microcurie so there would then be 1.85E12 gamma's per second per 50 curies.
How tricky is the instructor??
sf
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Don't forget to multiply the answer for the 1173.2 and 1332.5 kev gammas by .9998 to account for the yield.
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Why not just round off the the percent yeild to 100% ??? Is .0002 really going to make that much of a difference? I have never run accross any problem that acually needed to be that precise.
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As far as Radiography, 1.173 & 1.332 Mev, both @ 100% work!
If you didn't know about the two gamma photons associated with Co-60, wait till you get to Ir-192! :o
RG!
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As far as Radiography, 1.173 & 1.332 Mev, both @ 100% work!
If you didn't know about the two gamma photons associated with Co-60, wait till you get to Ir-192! :o
RG!
I seem to remember about 8 or 9 significant gammas (another many that aren't) , adding up to about 800 kev....
Hard lesson from my Tech A event..... ;)
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Hard lesson from my Tech A event..... ;)
I wonder how many of us have been Technician A at some point. :o I know I have...
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Lots of Tech "A" in the Radiography Industry!
RG!
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Marssim,
ISOCS & Radiography!
They go together like Peas and Wing Tips!
RG!
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http://en.wikipedia.org/wiki/Cobalt-60
Your answer is in here.
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ROFLMAO!
Your talking MAN....I'm talking MACHINE!
RG