NukeWorker Forum
Career Path => Radiation Safety => Topic started by: Zorro1 on Nov 30, 2015, 03:05
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I know the solution to this is probably simple but on problem set 9 of ch. 2 in Gollnick's Basic rad pro tech. it asks: Calculate the average energy of the negatron and neutrino emitted in the beta decay of 90Y..... the answers are (Beta = 0.758 MeV, neutrino = 1.52MeV) how did they come to this?
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Good question, thank you for asking.
Chapter 2, Page 44:
In beta decay, we often call this energy the endpoint energy or Emaximum. On the average, betas carry about 1/3 of the endpoint energy.
2.278 * 1/3 = 0.758
Chapter 2, Page 46:
Remember that the betas emitted have a range of energies up to the value of the decay energy, Emaximum. On the average, they carry 1/3 Emax and the neutrinos 2/3 Emax.
2.278 * 2/3 = 1.52