My instructor has asked a question that I don't know how to figure out. It is not in the assigned textbook which I have read cover to cover. Perhaps it needs a formula or some information not covered in this part of the class. Anyway here goes.
How many gamma rays are emitted from a 50 curie source of Co 60 in one minute?
Is there some formula to figure this out? Is this one of those so easy questions I am overlooking it?
Is this question even in the right place on this forum? LOL
I asked a couple of other students in my class and none of them have a clue, and the first time I will have to ask the instructor will be when I have to hand it in. :-[
1 Ci = 3.7E10 dis per second
each decay for Co-60 gives 2 gammas.
You have 50 Ci X3.7E10 dis/sec/Ci X2 gammas/dis X 60 sec/min
Its solved by unit analysis and doesn't need an equation from book.
ahhh there we go.. even though I didn't put in part of the question you gave me the answer.
or the way to figure it out.
How many gamma rays are emitted from a 50 curie source of Co 60 in one minute?
Was supposed to say..
How many 1.33 Mev gamma rays are emitted from a 50 curie source of Co 60 in one minute?
So 50 Ci x 37 billion dis/sec/ci x1 gamma/dis x 60 sec/min
I didn't know that each disintegration gave off the 2 characteristic gammas.
Quote from: stoicperrin on Oct 06, 2008, 03:08
ahhh there we go.. even though I didn't put in part of the question you gave me the answer.
or the way to figure it out.
How many gamma rays are emitted from a 50 curie source of Co 60 in one minute?
Was supposed to say..
How many 1.33 Mev gamma rays are emitted from a 50 curie source of Co 60 in one minute?
So 50 Ci x 37 billion dis/sec/ci x1 gamma/dis x 60 sec/min
I didn't know that each disintegration gave off the 2 characteristic gammas.
Here is some future reference material that may be helpful
http://www.nndc.bnl.gov/chart/ (http://www.nndc.bnl.gov/chart/) - an interactive chart of the nuclides
http://www.radprocalculator.com/Index.aspx (http://www.radprocalculator.com/Index.aspx) - the Rad Pro Calculator - a handy tool by Ray McGinnis
Then there is the study tab at the top of the website here - lots of information.
So, what course are you taking?
May be a trick question cause gamma's per second and disintegrations per second aint the same thing.
For Co-60 there are 3.699E4 gamma's per second per microcurie so there would then be 1.85E12 gamma's per second per 50 curies.
How tricky is the instructor??
sf
Don't forget to multiply the answer for the 1173.2 and 1332.5 kev gammas by .9998 to account for the yield.
Why not just round off the the percent yeild to 100% ??? Is .0002 really going to make that much of a difference? I have never run accross any problem that acually needed to be that precise.
As far as Radiography, 1.173 & 1.332 Mev, both @ 100% work!
If you didn't know about the two gamma photons associated with Co-60, wait till you get to Ir-192! :o
RG!
Quote from: RAD-GHOST on Oct 07, 2008, 07:21
As far as Radiography, 1.173 & 1.332 Mev, both @ 100% work!
If you didn't know about the two gamma photons associated with Co-60, wait till you get to Ir-192! :o
RG!
I seem to remember about 8 or 9 significant gammas (another many that aren't) , adding up to about 800 kev....
Hard lesson from my Tech A event..... ;)
Quote from: HouseDad on Oct 07, 2008, 08:50
Hard lesson from my Tech A event..... ;)
I wonder how many of us have been Technician A at some point. :o I know I have...
Lots of Tech "A" in the Radiography Industry!
RG!
Marssim,
ISOCS & Radiography!
They go together like Peas and Wing Tips!
RG!
http://en.wikipedia.org/wiki/Cobalt-60
Your answer is in here.
ROFLMAO!
Your talking MAN....I'm talking MACHINE!
RG