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Offline Zorro1

Gollnick problem... can't solve
« on: Nov 30, 2015, 03:05 »
I know the solution to this is probably simple but on problem set 9 of ch. 2 in Gollnick's Basic rad pro tech. it asks: Calculate the average energy of the negatron and neutrino emitted in the beta decay of 90Y..... the answers are (Beta = 0.758 MeV, neutrino = 1.52MeV)    how did they come to this?
« Last Edit: Nov 30, 2015, 03:05 by Zorro1 »

Offline Rennhack

Re: Gollnick problem... can't solve
« Reply #1 on: Nov 30, 2015, 06:28 »
Good question, thank you for asking.

Chapter 2, Page 44:
Quote
In beta decay, we often call this energy the endpoint energy or Emaximum. On the average, betas carry about 1/3 of the endpoint energy.

2.278 * 1/3 = 0.758


Chapter 2, Page 46:
Quote
Remember that the betas emitted have a range of energies up to the value of the decay energy, Emaximum. On the average, they carry 1/3 Emax and the neutrinos 2/3 Emax.

2.278 * 2/3 = 1.52
« Last Edit: Nov 30, 2015, 06:42 by Rennhack »

 


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